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- The Exercise Correction 4 natural integers numbers
- Solved Exercise 4 natural integers numbers
- The Exercise Correction 3 natural integers numbers
- Solved Exercise 3 natural integers numbers
- The Exercise Correction 2 natural integers numbers
- Solved Exercise 2 Natural number
- The Exercise Correction 1 natural integers numbers
- Solved Exercise 1 Natural number
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juin
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Correction 1) factorize the following expression : a= x²-5x+4 b= 2x²+3x-1 2) decompose 3240 and 1440 into a pro...
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Back to the exercise 1) a= x²-5x+4= x²- 2 x +1 - 3 x +3 =(x - 1 ) ² - 3 (x- 1) =(x - 1 )(x - 1 - 3 )= (x - 1 )(x - 4 ) b =2 x...
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Back to the exercise 1) we have for all primes numbers greater than 3 is are odd number , so there is an integer k for p = ...
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Correction 1) factorize the following expression : a= x²-5x+4 b= 2x²+3x-1 2) decompose 3240 and 1440 into a pro...
-
Back to the exercise 1) a= x²-5x+4= x²- 2 x +1 - 3 x +3 =(x - 1 ) ² - 3 (x- 1) =(x - 1 )(x - 1 - 3 )= (x - 1 )(x - 4 ) b =2 x...
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Back to the exercise 1) we have for all primes numbers greater than 3 is are odd number , so there is an integer k for p = ...
mardi 17 juin 2014
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Correction 1) factorize the following expression : a= x²-5x+4 b= 2x²+3x-1 2) decompose 3240 and 1440 into a pro...
-
Back to the exercise 1) a= x²-5x+4= x²- 2 x +1 - 3 x +3 =(x - 1 ) ² - 3 (x- 1) =(x - 1 )(x - 1 - 3 )= (x - 1 )(x - 4 ) b =2 x...
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Back to the exercise 1) we have for all primes numbers greater than 3 is are odd number , so there is an integer k for p = ...
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